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norbayamhdsimin

Published on December 4, 2014

Strength Of Materials Cantilever Beam 24 When x = L, dy/dx = 0. Replace into equation (1) 0 = 1 2 ) ( 2 C L W 1 C = 2 2 WL Then equation (1) will be dx dy EI = 2 2 2 2 WL Wx Maximum slope occurs at point A, where x = 0 max dx dy EI = 2 2 WL max dx dy = max = EI WL 2 2 The second integral will give EIy = 2 2 6 2 3 C x WL Wx -------------------------------------------------- (2) When x = L, y = 0, substitute into equation (2) 0 = 2 2 ) ( 6 ) ( 2 3 C L WL L W 2 C = 2 6 3 3 WL WL = 3 3 WL Equation (2) will be, EIy = 3 2 6 3 2 3 WL x WL Wx Maximum deflection, y m occurs at x = 0 EIy = 3 3 WL max y = EI WL 3 3 (Negative sign indicates downward deflection)