# 5101 number bases

October 12, 2014  |  By  |

1. Number bases 2 21 . 10100 2  1111 2 = A 101 2 C 1001 2 B 111 2 D 1011 2 [J 2008 Q6] 22 . 10101 2 – 11 2 = A 10000 2 C 10100 2 B 10010 2 D 10110 2 [N 2008 Q5] 23 . Express 204 8 as a number in base five. A 1012 5 C 2101 5 B 1304 5 D 4031 5 [N 2008 Q6] 24. State the value, in base 10, of the underlined digit in the number 101 10 2 . A 2 C 6 B 4 D 8 [J 2009 Q5] 25. 11001 2 111 2 = A 11100 2 C 100000 2 B 11110 2 D 100101 2 [J 2009 Q6] 26. Express 176 8 as a number in base five. A 101 5 C 231 5 B 126 5 D 1001 5 [Trial SBP 2004 Q5] 27. 43 5 111 2 = A 10010 2 C 11110 2 B 11010 2 D 11111 2 [Trial SBP 2004 Q6] 28. 10101 2  1010 2 = A 1011 2 C 1101 2 B 1111 2 D 1001 2 [Trial SBP 2005 Q5] 29. Express 8 243 as a number in base two. A 11110011 2 C 10100011 2 B 11001111 2 D 11000101 2 [Trial SBP 2005 Q6] 30. Express 253 8 as a number in base five. A 1141 5 C 1411 5 B 171 5 D 164 5 [Trial SBP 2006 Q5] 31. 10110 2 – 1011 2 = A 1011 2 C 1111 2 B 1101 2 D 10011 2 [Trial SBP 2006 Q6] 32 . 10101 2 – 1001 2 = A 1000 2 C 1100 2 B 1010 2 D 1110 2 [Trial SBP 2007 Q4] 33. What is the value of digit 3 in base five in the number 49 328 10 ? A 1200 C 2200 B 2020 D 2220 [Trial SBP 2007 Q5] 34. Express 2341 5 as a number in base 8. A 346 8 C 532 8 B 436 8 D 623 8 [Trial SBP 2008 Q4] 35. Evaluate 11010 2  1101 2. A 1011 2 C 10001 2 B 1101 2 D 10011 2 [Trial SBP 2008 Q5] 36. 10100 2  1001 2 = A 1101 2 C 1001 2 B 1011 2 D 111 2 [ [Trial SBP 2009 Q4] 37 . Find the value of digit 3 for the number 4302 5 in base ten. A 75 C 85 B 80 D 150 [Trial SBP 2009 Q5] 38 . State the value of digit 5 in the number 1536 8 , in base 10. A 40 C 320 B 64 D 500 [N 2009 Q5] 39 . 11100 2 – 1010 2 = A 10000 2 C 10100 2 B 10010 2 D 10110 2 [N 2009 Q6] 40. What is the value of the digit 1, in base ten, in the number 2104 5 ? A 5 C 100 B 25 D 125 41. What is the value of the underlined digit, in base ten, in the number 111 0110 2 ? A 2 C 8 B 4 D 16