Explore Flipsnack. Transform boring PDFs into engaging digital flipbooks. Share, engage, and track performance in the same platform.
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Here are eight reasons why you should consider choosing interactive, digital flipbooks instead of boring and static PDFs. Check them out!
⇒ Q.3 : Show that the diagonals of a parallelogram divide it into four triangles of equal area. Solution: We know that diagonals of parallelogram bisect each other. Therefore, O is the mid-point of AC and BD. BO is the median in ΔABC. hereore, it ill diide it into to triangles o eal areas. ∴ Area (ΔAOB) = Area (ΔBOC) … (1) In ΔBCD, CO is the median. ∴ Area (ΔBOC) = Area (ΔCOD) … (2) Similarly, Area (ΔCOD) = Area (ΔAOD) … (3) From equations (1), (2), and (3), we obtain Area (ΔAOB) = Area (ΔBOC) = Area (ΔCOD) = Area (ΔAOD) Therefore, it is evident that the diagonals of a parallelogram divide it into four triangles of equal area. Q. 4 : In the given figure, ABC and ABD are two triangles on the same base AB. If line-segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD). Solution: Consider ΔACD. Line-segment CD is bisected by AB at O. Therefore, AO is the median of Δ ACD. ∴ Area (ΔACO) = Area (ΔADO) … (1) Considering ΔBCD, BO is the median. ∴ Area (ΔBCO) = Area (ΔBDO) … (2)
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